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Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.​

User Egirus Ornila
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1 Answer

15 votes
15 votes

Answer:


\textsf{area of a sector}=(\theta\pi r^2)/(360\textdegree) \mathsf{\ \ (where\ \theta \ is\ in\ degrees)}

Given:

  • radius (r) = 6 cm

  • \theta = 60°


\implies \textsf{area}=(60\textdegree *\pi * 6^2)/(360\textdegree)


\implies \textsf{area}=(2160\pi)/(360)


\implies \textsf{area}=6\pi \textsf{ cm}^2


\implies \textsf{area}=18.85\textsf{ cm}^2 \textsf{ (nearest hundredth)}

User August Bjornberg
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