menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Register
Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question
Could someone please answer with a step by step explanation?
asked
Aug 9, 2022
30.1k
views
4
votes
Could someone please answer with a step by step explanation?
Mathematics
college
Dina
asked
by
Dina
4.4k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1
Answer
4
votes
Express
as a single fraction.
The least common multiple of 2 and 8 is 8. Convert 1 / 2 and 3 / 8 to fractions with denominator 8.
Because 4 / 8 and 3 / 8 have the same denominator, subtract them by subtracting their numerators.
Subtract 3 from 4 to get 1.
Multiply 4 and 1 / 8 to get 4 / 8.
Reduce the fraction 4 / 8 to its lowest terms by extracting and cancelling out 4.
The least common multiple of 4 and 2 is 4. Convert 9 / 4 and 1 / 2 to fractions with denominator 4.
Because 9 / 4 and 2 / 4 have the same denominator, add them by adding their numerators.
Add 9 and 2 to get 11.
Convert 2 to fraction 8 / 4.
Add 11 and 8 to get 19.
Yan Koshelev
answered
Aug 13, 2022
by
Yan Koshelev
4.3k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
4.5m
questions
5.8m
answers
Other Questions
Before beginning voice lessons, Aubrey already knew how to sing 357 pieces, and she expects to learn 2 new pieces during each week of lessons. After 78 weeks of voice lessons, how many pieces will Aubrey
Solve for x in the equation 3 x squared minus 18 x + 5 = 47. (I need this to be an answer like X=3+\_ square root 23)
Please answer asap.......... ...
Can someone help me plz I have to Turn 27/9 in simplest
What value of x makes the following true? 2(x + 10) = 4( 2x - 1)
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org