Question

ABCD is an isosceles trapezoid with legs AB and CD and with base BC. If AB=6z - 5 and BC = 7z +4 and CD = 4z +3

Answer 1

Explanation:

As it is an isosceles trapezoid,

AB = CD

6z - 5 = 4z + 3

To find the value of z, isolate z.

Add 5 to both sides

6z = 4z + 3 + 5

6z = 4z + 8

Subtract 4z from both sides

6z - 4z = 8

2z = 8

Divide both sides by 2

z = 8/2

z = 4

AB = 6z - 5

= 6*4 - 5

=24 - 5

AB = 19

CD = 4z + 3

= 4*4 +3

= 16 +3

CD = 19

BC = 7z + 4

= 7*4 + 4

= 28 + 4

BC = 32