Question

Write the equation of the line that is parallel to x – 3y = 9 and passes

through the point (3, -1).

Answer 1

x – 3y = 9 ⇔ y =
`(1)/(3) x + 3`

the line parallel is y' =
`(1)/(3)x + b (b\\eq 3)`

y' =
`(1)/(3)x + b (b\\eq 3)` passes through (3, -1) --> -1 =
`(1)/(3)` × 3 + b --> b = -2

⇒ y' =
`(1)/(3) x - 2`