Question

HII SOMEONE HELPPP PLEASE ​‼️‼️‼️

Answer 1

Explanation:

Fame age be x and sister's age = y

Five years ago:

Fame's age = x - 5

His sister's age = y -5

`x -5 =(1)/(6)*(y-5)\\\\`

Multiply the entire equation by 6

`6*(x-5)=6*(1)/(6)(y-5)\\`

6x- 6*5 = y-5

6x - 30 = y - 5

6x -30 + 5 = y

y = 6x - 25--------------(I)

Three year after:

Fame's age = x + 3

His sister's age = y + 3

2*(x +3) = y + 3

2x + 6 = y + 3

2x + 6 -3 = y

y = 2x + 3 -------------(II)

Substitute y = 6x - 25 in equation (II)

6x - 25 = 2x + 3

Add 25 to both sides

6x = 2x + 3 + 25

6x = 2x + 28

Subtract 2x from both sides

6x - 2x = 28

4x = 28

Divide both sides by 4

x = 28/4

x = 7

Substitute x = 7 in equation (I)

y =6x - 25

y = 6*7 - 25

= 42 - 25

y = 17

Fame's age = 7 years

His sister's age = 17 years

4) Let the distance between X and Y be D

Time take by Wie = distance÷ speed

`= (D)/(75)`

Time taken by Wary = distance ÷ speed

`=(D)/(80)`

Time difference = 10 minutes.

As Wary drives in high speed that Wie, he takes less time

`(D)/(75)-(D)/(80)= (10)/(60)\\\\`

LcM = 1200

`(16D)/(75*16)-(15D)/(85*15)=(1)/(6)\\\\\\(16D-15D)/(1200)=(1)/(6)\\\\\\(D)/(1200)=(1)/(6)\\\\\\D=(1)/(6)*1200\\\\\\`

D = 200 Km