Question

Find three consecutive integers that have the sum of -402

Answer 1

-135, -134, -133

Explanation:

Hi there!

Let x be equal to the first integer in the set of three consecutive integers.

Let x+1 and x+2 be the consecutive integers.

We're given that they have a sum of -402.

We can construct an equation:

`(x)+(x+1)+(x+2)=-402`

Combine like terms:

`x+x+1+x+2=-402\\x+x+x+1+2=-402\\3x+3=-402\\3x=-405\\x=-135`

Therefore the first integer is -135.

The next two consecutive integers after -135 is -134 and -133.

Therefore, the three consecutive integers are -135, -134 and -133.

I hope this helps!