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45 votes
45 votes
Find the remainder when p(x) = x4 - 27 is divided by x - 4.

User Tjw
by
3.2k points

2 Answers

23 votes
23 votes

Answer:

229

Step-by-step explanation:

Here we are given a polynomial p(x) and we need to find the remainder when it is divided by (x-4) . As we know that if a polynomial, say
g(x) is divided by
x-a then the remainder is
g(a) .

Firstly equate
x -4 with 0 , we have;


\longrightarrow x -4=0\\


\longrightarrow x =0+4\\


\longrightarrow x = 4

Now substitute
x =4 in
p(x) ,


\longrightarrow p(x)= x^4-27\\


\longrightarrow p(4)= (4)^4-27\\


\longrightarrow p(4) = 256 - 27 \\


\longrightarrow \underline{\underline{\boldsymbol{ p(4) = 229}}}

Hence the remainder is 229 .

User John Haugeland
by
3.2k points
14 votes
14 votes

Answer:

229 is the remainder.

Step-by-step explanation:

In order to find the remainder, insert the value of x in the equation.

Given equation:


  • \sf p(x) = x^4 - 27

Given x value:

  • x - 4 = 0
  • x = 4

Find remainder:


\sf p(4) = 4^4 - 27


\sf p(4) = 256 - 27


\sf p(4) = 229

User Dmitry Meyer
by
2.6k points