![\huge \boxed{\mathfrak{Question} \downarrow}](https://img.qammunity.org/2022/formulas/business/college/w7rd9ddf5swaqx6h7w2rdc7fe2s24fsc06.png)
![\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}](https://img.qammunity.org/2022/formulas/business/college/6rihqyi13zmt3iigtmkd6hstdpaj7k3civ.png)
Given, K is the midpoint of JL. So, JK = KL.
- KL = 14x - 1
- JK = 8x + 11
- JL = ?
________
JL = JK + KL (given that K is the midpoint of JL)
JL = (8x + 11) + (14x - 1)
________
![\large \boxed{\mathfrak{Steps} \downarrow}](https://img.qammunity.org/2022/formulas/mathematics/high-school/1sen3k9htw364rlnj1j4zjg8ts5lk93akz.png)
![\sf( 8 x + 11 ) + ( 14 x - 1 )](https://img.qammunity.org/2022/formulas/mathematics/high-school/mmex38gg139jezmpaef79tjgh7goz2our0.png)
Combine 8x and 14x to get 22x.
![\sf \: 22x+11-1](https://img.qammunity.org/2022/formulas/mathematics/high-school/jqabgt94d2898mgjmu833z0qz2o250djs5.png)
Subtract 1 from 11 to get 10.
![\boxed{ \boxed{ \bf22x+10 }}](https://img.qammunity.org/2022/formulas/mathematics/high-school/xoj9d22wvspuhld92agjmzz0hwhv97vqxn.png)
________
Also given that, JK = KL.
So, (8x + 11) = (14x - 1)
⇨ (8x + 11) = (14x - 1)
⇨ 8x + 11 = 14x - 1
⇨ 11 + 1 = 14x - 8x
⇨ 12 = 6x
⇨ x = 12 / 6
⇨
![\boxed{ \boxed{ \bf \: x= 2 }}](https://img.qammunity.org/2022/formulas/mathematics/high-school/m0oyvxr2b6ybxldb3ncsbg5048ai4wzxxs.png)
________
Now, value of JL will be,
JL = 22x + 10
Substitute the value of x.
JL = 22(2) + 10
JL = 44 + 10
![\boxed{ \boxed{ \bf\: JL = 50 }}](https://img.qammunity.org/2022/formulas/mathematics/high-school/y3fzi0z9l73pmcg4w0trrl2lin0hssv3tv.png)
⇨ So, the value of JL will be 50 units.