Question

Find the length of the third side. If necessary, round to the nearest tenth 22 25

Answer 1

• This is Right Angled Triangle.

• We'll solve this using the Pythagorean Theorem.

Let,

• Let BC be perpendicular.

• 22 be AB, where AB is the Base.

• 25 be AC, where AC is the Hypotenuse.

We know that,

`{ \longrightarrow \bf \qquad \: (AB) {}^(2) +( BC) {}^(2) = (AC) {}^(2) }`

`{ \longrightarrow \sf \qquad \: (22) {}^(2) +( BC) {}^(2) = (25) {}^(2) }`

`{ \longrightarrow \sf \qquad \: (BC) {}^(2) = (25) {}^(2) - ( 22) {}^(2) }`

`{ \longrightarrow \sf \qquad \: BC = \sqrt{(25) {}^(2) - ( 22) {}^(2)} }`

`{ \longrightarrow \sf \qquad \: BC = √(625 - 484) }`

`{ \longrightarrow \sf \qquad \: BC = √(141) }`

`{ \longrightarrow \bf \qquad \: BC \approx11.87 }`

Therefore,

• The length of the third side is 11.9 (Nearest tenth of 11.87) .

Answer 2

Explanation:

According to Pythagoras theorem ,

Hypotenuse² = Perpendicular ² + Base ²

Here , we have to find perpendicular

• Hypotenuse = 25 unit
• Base = 22 unit

So,

Hypotenuse² - Base² = Perpendicular²

putting the known values

25² - 22² = perpendicular²

141 = perpendicular²

√141 = perpendicular

Perpendicular = 11.9 unit