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Jannelle · Answer 1 · 2022-11-01T20:27:41+0000

Answer:Solving these equations, we see that, beginning with 6.0 grams of aluminum, 0.22 moles of AlCl3 can be formed, and that, beginning with 3.8 grams of chlorine, 0.036 moles of AlCl3 can be formed.

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