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What is the mass of a 15 cm^3 piece of iron if the density of iron is 7.87G/ML

1 Answer

3 votes

Answer:

118.05 grams

Step-by-step explanation:

mL = cm³

Density = mass/volume

Let x = mass

Our equation will look like this: x/15 = 7.87

Multiply both sides by 15 to isolate the variable, x

15(x/15) = 15(7.87)

15x/15 = 118.05

x = 118.05

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