Question

Find the equation of the line that passes through the point

(4, 11) and is perpendicular to y= 4/3x + 7

Answer 1

y = -3/4x + 14

Explanation:

The slope of a perpendicular line is the opposite reciprocal of the original line.

4/3x -> -3/4x

Now we need to find the y-intercept and we can do that by using the slope intercept form expression [ y = mx + b ].

11 = -3/4(4) + b

11 = -3 + b

14 = b

Put everything we know and solved for back into the expression.

y = -3/4x + 14

Best of Luck!