Question

Does anybody know this

Answer 1

Explanation:

The equation used to determine the amount of radioactive material left is

`A = A_0(2)^(-t/HL)`

We are have the following given quantities:

t = 30 seconds

`A_0` = 50 grams

HL = 6 seconds

Plugging these into our equation we get

`A = (50\:\text{grams})(2)^(-(30s/6s))`

`\:\:\:\:= (50\:\text{grams})(0.03125)`

`\:\:\:\:= 1.56\:\text{grams}`