Question

How many ounces of a 15​% alcohol solution must be mixed with 4 ounces of a 20​% alcohol solution to make a 17​% alcohol​ solution?

Answer 1

Therefore 2 ounces of 11% alcohol solution must be mixed with 4 ounces of 20%alcohol to make a 17%alcohol solution

Explanation:

Let x ounces of 11% alcohol must be mixed with the 2 ounces of 20% alcohol.

The amount of alcohol in 4 ounces solution is= ounces

= 0.8 ounces

The amount of alcohol in x ounces solution is= ounces

= 0.11 x ounces

Total amount of alcohol is = (4+x) ounces

According to the problem,

Therefore 2 ounces of 11% alcohol solution must be mixed with 4 ounces of 20%alcohol to make a 17%alcohol solution

Answer 2

6 ounces

Explanation:

Let x = the number of ounces of the 15% alcohol solution needed to be mixed with the 4 ounces of 20% alcohol solution to obtain the 17% alcohol solution.

After converting the percentages to their decimal equivalents, set up the necessary equation as follows:

0.15x+0.20(4) = (x+4)(0.17) Simplify and solve for x.

0.15x+0.8 = 0.17x+0.68 Subtract 0.15x from both sides.

0.8 = 0.02x+0.68 Now subtract 0.68 from both sides.

0.12 = 0.02x Finally, divide both sides by 0.02

x = 6

You need to mix 6 ounces of 15% alcohol solution with 4 ounces of 20% alcohol solution to obtain 10 (x+4)ounces of 17% alcohol solution.