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What least number must be divided from 8192 to make it a perfect cube?​

User MartinT
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\displaystyle\bf\\8192 = 2^(13)~~~It~is~not~a~perfect~cube,~but~2^(12)~is~a~perfect~cube.\\\\\implies~We~have~to~divide~the~number~8192~by~2.\\\\(8192)/(2)=4096=2^(12)=2^(4*3)=\big(2^4\big)^3=16^3=perfect~cube

User Talves
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