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Tìm x, y, z biết x(x+y+z )=-5; y(x+y+z )=9;7(x+y+z )=5

User Sanketh
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1 Answer

3 votes

Answer:

Explanation:

Có: 7(x+y+z)=5

=>x+y+z = 5/7 (1)

Lại có:

+) y(x+y+z)=9

=>y×5/7=9

y=9: 5/7

y=63/5 (2)

+) x(x+y+z)=-5

=>x×5/7=-5

x=-5:5/7

x=-7 (3)

Từ (1);(2) và (3) => -7+63/5+z =5/7

=>28/5+z=5/7

=>z=-171/35

Vậy ....

User Muhammad Azeez
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