Question

Suppose you are playing pool with a friend. The white cue ball

travels 10 m/s toward the black eight-ball, which is at rest. After
they collide, the cue ball is at rest and the eight-ball is moving.
Both have a mass of 0.16 kg. How fast is the eight-ball moving?
m/s

Answer 1

10 m/s

Step-by-step explanation:

u of cue ball = 10 m/s

u of eight ball=0m/s

m of cue ball =0.16 kg

m of eight ball =0.16 kg

According to law of conservation of momentum

Momentum before collision = Momentum after collision

so

( m of cue ball X velocity of cue ball) + ( m of eight ball X velocity of eight ball)= (m of cue ball X velocity of cue ball after collision )+( m of eight ball X velocity of eight ball after collision)

thus

(0.16 X 10)+(.016 X 0)= (0.16 X 0)+ ( 0.16 X velocity of eight ball after collision)

1.6= 0.16 X velocity of eight ball after collision

1.6÷0.16= velocity of ball after collision

10= velocity of eight ball after collision