Question

How many moles of LiOH are needed to react completely with 25.5 g of CO2

Answer 1

3.18 mol

Step-by-step explanation:

`2LiOH+CO_(2)-> Li_(2)CO_(3) +H_(2)O`

n(CO2) = mass/ Mr.

= 25.5 / 16

= 1.59 mol

As per the equation above,

n(LiOH) : n(CO2)

2 : 1

∴ 3.18 : 1.59