Question

Simplify the radical

`- 2 √(54)`
please explain process!​

Answer 1

`\huge \boxed{\mathfrak{Question} \downarrow}`

• Simplify
  `\sf \: - 2 \sqrt { 54 }`

`\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}`

`\sf \: - 2 \sqrt { 54 }`

• Factor
  `\sf54=3^(2)* 6`.
• Rewrite the square root of the product
  `\sf\sqrt{3^(2)* 6}` as the product of square roots
  `\sf \sqrt{3^(2)}√(6)`.
• Take the square root of
  `\sf3^(2)`.

`\sf-2* 3√(6)`

• Multiply -2 and 3 to get -6.

`\boxed{ \boxed{ \bf-6√(6) }}`

• The answer will be
  `\boxed{\sf-6√(6) }`. If you want you can further simplify it to - 14.696..

Answer 2

Explanation:

54 = 6*9

That means there are 3 threes and 1 two

54 = 2*3 * 3 * 3

There are a pair of 3s and a two and a 3 left over.

The two and the three remain under the root sigh.

One of the pair of threes comes out of the root sign.

The other one is thrown away.

sqrt(54) = 3*sqrt(6)

Answer: -2*3 sqrt6)

Answer: - 6 sqrt(6)