Find the smallest value of k, such that 693k is a perfect cube.

asked May 22, 2022 212k views

3 votes

4.0k points

Please log in or register to add a comment.

5 votes

Answer:

$(8^3)/(693)=(512)/(693)\quad \left(\mathrm{Decimal:\quad }\:0.73881\dots \right)$

Explanation:

Faris Muhammed answered May 25, 2022

4.1k points

3 votes

Answer:

MGMHMHMHNHMMJMMMH

BSEHEJR

3.8k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.3m questions

5.6m answers