Question

Stan's, Mark's, and Wayne's ages are consecutive whole numbers. Stan is the youngest, and Wayne is the oldest. The sum of their ages is 111. Find their ages.

Answer 1

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Given conditions,

• Stan's, Mark's & Wayne's ages are of consecutive whole numbers.

• Stan is the youngest of all.

• Wayne is the oldest of all.

• The sum of their ages is 111.

Let Stan's age be x, Mark's age be (x + 1) & Wayne's age be (x + 2).

According to the conditions,

⇒x + (x + 1) + (x + 2) = 111

⇒x + x + x + 1 + 2 = 111

⇒3x + 3 = 111

⇒3x = 111 - 3

⇒3x = 108

⇒ x = 108/3

⇒ x = 36

Hence,

• Stayn's age will be x = 36 years.

• Mark's age will be (x + 1) = 36 + 1 = 37 years.

• Wayne's age will be (x + 2) = 36 + 2 = 38 years.

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