Answer:
71. 19 72. 100 73. 9 74.1 75. 90 76. 4
Explanation:
#71.
Start with 2b-a
Plug in the given numbers where the variables are.
Now the equation is 2(12) - 5
Solve 2(12) - 5
2(12) = 24 24 - 5 = 19
#72.
Start with d(ab-c)
Plug in the given numbers where the variables are.
Now the equation is 2((5×12) - 10)
Solve in the parenthesis first.
5×12= 60 60-10=50 2(50)= 100
#73.
Start with 3+

Plug in the given numbers where the variables are.
Now the equation is 3+

Solve.
= 6 3+6 = 9
#74.
Start with

Plug in the given numbers where the variables are.
Now the equation is

Solve.
4(5)= 20
(4×2)= 8 12+8= 20
Now the fraction is
= 1
#75.
Start with 2a² - c
Plug in the given numbers where the variables are.
Now the equation is 2(5)² - 10
Solve 2(5) = 10 10² = 100 100-10= 90
#76.
Start with b - c + d
Plug in the given numbers where the variables are.
Now the equation is 12 - 10 + 2
Solve.
12 - 10 = 2 2 + 2 = 4