Question

Solve the radical equation, if possible.

Answer 1

Answer: C

Explanation:

3x-3 ≥ 0 ==> x ≥ 1

3x+6 ≥ 0 ==> x ≥ -2

So: condition x ≥ 1

`√(3x-3) +1=√(3x+6) \\\\√(3x+6) -√(3x-3) =1 \ squaring\\\\3x+6+3x-3-2√((3x+6)(3x-3)) =1\\\\6x+2=2√((3x+6)(3x-3))\\\\√((3x+6)(3x-3))=3x+1\ squaring \\\\(3x+6)(3x-3)=(3x+1)^2\\\\9x^2+18x-9x-18=9x^2+6x-1\\\\3x=19\\\\x=(19)/(3) \\\\sol=\{(19)/(3)\}\\\\Answer\ C\\`