Answer:
50%
Step-by-step explanation:
The other person is right but not for the right reasons. Over here, we have some applications to punnet squares and genes. Over here, we're discussing genotypes.
Also, having color in your eyes is a dominant gene while having colorblindness is a recessive gene (as shown in the question since the carrier female must be heterozygous and is still not colorblind).
So we can set up a punnet square here to lead us through it.
We will use C as our letter. C will be the dominant trait and c will be the recessive trait (dominant is having color, recessive is being colorblind).
__c__c_
C|Cc| Cc
c|cc | cc
I made the box to the best of my ability but it was still difficult
Since having color is dominant, wherever you see Cc (alleles of dominant and recessive), the offspring will have the dominant trait (having color).
To have the recessive gene (colorblindness), you need to have both the recessive genes. In this case, it would be cc.
2/4 of the possibilities would result in the offspring having color (Cc, Cc) which is 50%
2/4 of the possibilities would result in the offspring being colorblind (cc, cc) which also correlates to 50%.
That's how you get 50% as your answer.
Let me know if you have any questions.