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Show that a to the 6th an be written as a perfect square and as a perfect cube.

1 Answer

5 votes

Answer:

Explanation:

a^6 = a * a * a * a * a * a You can break this into groups of 2 and groups of three.

Groups of 3

a^6 = a * a * a * a * a * a

what that means is that you have 2 groups of 3 which can be written as (a^3)^2 which means that this number is a perfect square.

Groups of 2

a^6 = a * a * a * a * a * a

What this means is that you have (a^2)^3 which is three groups of 2 members. The answer is that you have a perfect cube each member of which is a^2

User Horia Coman
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