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A substance was analysed and found to contain 26.57 % potassium, 35.36% chromium, and

38.07 % oxygen by mass.
What is the empirical formula of the substance?

Select one:
question
O a. K2Cr205
O b. K2Cr207
O c. KCr2O7
O d. K_Cro

User Sarusso
by
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1 Answer

5 votes

Answer: K2Cr2O7

Explanation: Pretend we have 100g of the compound. use the percentage to calculate how many grams of each element are in the 100g.

K: 26.57g

Cr: 35.36 g

O: 38.07 g

Now divide by the molar mass of each element to find the moles of each:

K: 0.7 moles

Cr: 0.7 moles

O: 2.4 moles

That gives us 3.8 moles total. But what's important is to find a factor that would bring all of these mole values to a whole number, since they must be in whole number proportions. The closest I got was around 3.

That would lead to the following empirical formula: K2Cr2O7.

User HBMCS
by
4.1k points