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Urkar is driving down the street at 11 m/s. What acceleration is required for him to slow to a stop in 2 s?

1 Answer

2 votes

Answer:

-5.5m/s^2

Step-by-step explanation:

Well first of all, we know that velocity is a vector, therefore acceleration is a vector. And since urkar is slowing down, the acceleration will be negative

V1 = 11m/s

V2 = 0m/s ( bcuz they said to a stop)

t = 2s

a = V2 - v1

- - - - - - - - - -

t

a = 0 - 11

- - - - - - -

2

= - 5.5ms^-2

User Aken Roberts
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