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Rolls of foil are 300mm wide and 2.020mm thick. (The density of foil is 2.7 g/cm^3). What maximum length of foil can be made from 1.40 kg of foil?

1 Answer

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Answer: 8556 mm, or 855.6 cm (8560 mm to 3 sig figs)

Explanation: Convert mm to cm by dividing by 10 (1cm/10mm)

Find the area of the foil face in cm^2 (30cm*0.2020cm) = 0.606 cm^2

Calculate the volume occupied by 1.40 kg of foil in cm^3. 1.40kg = 1400g

1.400g/(2.7 g/cm^3) = 518.5 cm^3 for 1.40 kg Au

Volume = Area (of the face) * Length

We want Length:

Length = Volume/Area

L = (518.5 cm^3/0.606 cm^2)

L = 855.6 cm (8556 mm) Round to 3 sig figs (856 cm and 8560 mm)

User Pattabhi
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