I am guessing that you mean 2cos2(45° - A) = 1 + sin2A
According to a double angle identity, 2cos2θ - 1 = cos(2θ)
So, 2cos2(45° - A) - 1
= cos (90° - 2A) =cos90°cos2A + sin90°sin2A = (0)cos2A + (1)sin2A = sin2
Thus, 2cos2(45° -A ) = 1 + sin2A
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