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If (x + 4)^2 = 49 and x <0, what is the value of x?
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If (x + 4)^2 = 49 and x <0, what is the value of x?

User Andrewjamesbowen
by
3.8k points

1 Answer

3 votes

Answer:

x = - 11

Explanation:

Take the square root of both sides.

sqrt(x+4)^2 = sqrt(49)

x + 4 = +/- 7

x + 4 = + 7

x = 3 Not what you want.

x + 4 = - 7

x = - 11

User Darsh
by
4.3k points
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