Answer:
Explanation:
It seems like there is only one question. I'll answer that first and then we'll discuss what might be inferred from the introduction.
1)
The way the problem is set up you get a factoring to take place
(x^3 - 8) = (x - 2)(x^2 + 2x + 4)
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(x - 2)
This question is unique. They expect you to cancel, which leaves you with y = x^2 + 2x + 4) which is a quadratic.
The reason you don't put in x = 2 is because technically, you get 0/0 which can be shown to be either 1 or 0. To get out of that, we say that 0/0 is undefined. The graphing program has taken the stance that 0/0 is 1. However I wouldn't really accept that. The whole problem comes down to 0/0 which is undefined.