Question

Find the area of trapezium whose parallel side are 10 and 12 cm. And height is 7 cm

Answer 1

77 cm²

Explanation:

We know that

Area of trapezium = ½ (a + b) × h

Area = ½ × (10 + 12) × 7

Area = ½ × 22 × 7

Area = 11 × 7

Area = 77 cm²

Answer 2

Given :

Length of parallel sides = 10 cm and 12 cm

Height = 7 cm

What To Find :

Area of trapezium

Formula Using :

`\begin{gathered} {\underline{\boxed{ \rm {\red{Area \: of \: trapezium \: = \: (1)/(2) \: * \: (a \: + \: b) \: * \:Height }}}}}\end{gathered}`

Where ,

• a and b is Parallel sides

Solution :

`\begin{cases} \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \: (1)/(2) \: * \: (10 \: + \: 12) \: * \:7 \\ \\ \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \: (1)/(2) \: * \: 22\: * \:7 \\ \\ \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \: (1)/( \cancel2) \: * \: \cancel{22} \: ^(11) \: * \:7 \\ \\ \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \:11 \: * \: 7 \\ \\ \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \:77 \: {cm}^(2) \end{cases}`