Someone please help me answer this ASAP<3

Question

asked Nov 13, 2023 190k views

1 Answer

Veera Raj · Answer 1 · 2023-11-19T12:26:49+0000

Answer:

C

Explanation:

To solve an equation of the form
ax^2+bx+c=0

Use completing the square formula:

$a\left(x+(b)/(2a) \right)^2+c-(b^2)/(4a)=0$

Given equation:

2x^2+16x-8=0

Therefore,

Substitute these values into the formula:

$2\left(x+(16)/(2(2)) \right)^2+(-8)-(16^2)/(4(2))=0$

$2\left(x+4} \right)^2-40=0$

To solve, add 40 to both sides:

2(x+4)^2=40

Divide both sides by 2:

(x+4)^2=20

Square root both sides:

$x+4=\pm √(20)$

$x+4=\pm √(4 \cdot 5)$

$x+4=\pm 2√(5)$

subtract 4 from both sides:

$x=-4\pm 2√(5)$