Question

PLEASE HELP

The pressure at the top of a liquid
is zero. At a depth of 0.589 m, the
fluid pressure is 4910 Pa. What is
the density of the fluid?
(Unit = kg/m^3)
(1 atm = 101300 Pa)

Answer 1

849.76

Step-by-step explanation:

The pressure p = ρgh where ρ is the density of the fluid, g is the acceleration due to gravity and h is the height of the fluid above the point in question.

So, we know p = 4910 = ρ(9.81)(0.589)

So ρ = 4910/5.778 = 849.76

The density of the liquid is 849.76kg/m^3

Answer 2

850.63 kg/m^3

Step-by-step explanation:

p=pgh

4910 = pxq .8x 0.589

p= 850.63 kg/m^3

this is what i got