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Determine the value of k for which the graph of y=kx^3 pass through the point (-2,1)

User Ulysse BN
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1 Answer

4 votes

Answer:


\displaystyle k = -(1)/(8)

Explanation:

We are given the equation:


\displaystyle y = kx^3

And we want to determine the value of k such that the graph passes through the point (-2, 1).

Hence, when x = -2, y = 1. Substitute:


\displaystyle (1) = k(-2)^3

Simplify:


\displaystyle 1 = -8k

Hence:


\displaystyle k = -(1)/(8)

User Adesina
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