Question

Question in the picture

Answer 1

I believe it would be
`a_(n) = -4 *(-2)^(n-1); -64` aka the second option.

Explanation:

In this example we have
`a_(1) = -4, r =2, n=5\\`

to find
`a_(5)` we use formula
`a_(n)=a_(1) * r^(n-1)`

. After substituting these values to above formula, we obtain:

`a_(n)=a_(1) * r^(n-1)\\a_(5) = -4* (-2)^(5-1)\\ a_(5) =-4 * 16\\a_(5) =-64`

hope this was helpful :)