Question

Can anyone do this with steps ..

Answer 1

`\\ \sf\longmapsto \displaystyle{\lim_(x\to 0)}(sinx-sin3x)/(sins3x-sinx)`

`\boxed{\sf \displaystyle\lim_(x\to 0)(f(x))/(g(x))=(\lim_(x\to 0)f(x))/(\lim_(x\to 0)g(x))}`

Now

`\\ \sf\longmapsto \displaystyle{(\lim_(x\to 0)sinx-\lim_(x\to 0)sin3x)/(\lim_(x\to 0)sin3x-\lim_(x\to 0)sinx)}`

`\boxed{\sf \displaystyle{\lim_(x\to 0)}f(x)=f(a)}`

`\\ \sf\longmapsto (sin0-sin3(0))/(sin3(0)-sin0)`

`\\ \sf\longmapsto (0-0)/(0-0)`

`\\ \sf\longmapsto (0)/(0)`

`\\ \sf\longmapsto 0`