Question

I need help on the steps.
5 + d > 5-d

Answer 1

`\huge\boxed{\boxed{\sf{d > 0}}}`

Explanation:

Hello.

First, move all the d's to the left. Be sure to use the opposite operation.

5+d>5-d (in this case, we subtract d, so the opposite operation is: add d)

5+d+d>5-d+d

The d's cancel out on the right:

5+d+d>5

Add the d's (they are like terms)

5+2d>5

Now, move 5 to the right, using the opposite operation:

5-5+2d>5-5

The 5's cancel out on both sides:

2d>0

Divide both sides by 2:

d>0, since 0 divided by 2 is 0 :)

And we're done!

I hope it helps & have an outstanding day!

~ST2710 :)

Answer 2

Explanation:

5 + d < 5 - d

Add 'd' to both sides

5 + d + d > 5 - d + d

5 + 2d > 5

Subtract 5 from both sides

5-5 + 2d > 5 - 5

2d > 0

d > 0

The value of d is all positive integers