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The upward normal force exerted by the floor is 620 n on an elevator passenger who weighs 650 n
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The upward normal force exerted by the floor is 620 n on an elevator passenger who weighs 650 n

User Zevero
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2 votes

Answer:


\alpha = 0.45 (m)/(s^(2) ) downward

Step-by-step explanation:

Hope this helps

User Dribbel
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