Question

A 0.450 M solution of HCl is prepared by adding some 1.50 M HCl to a 500 mL volumetric flask and diluting to the mark with deionized water. What volume of 1.50 M HCl must be added

Answer 1

150 mL of 1.50 M HCL

Step-by-step explanation:

So the equation you need to solve this equation is:

M1*V1=M2*V2 --> M1= Molarity of the acid you are diluting V1= Volume of the solution you need to dilute. M2=The molarity of thee solution you have made. V2=Volume of the solution you have made

M1= 1.50 M HCL

V1= Unknown

M2=0.450 M HCL

V2= 500 mL

Simple algebra says that V1= (1.5*500)/.450 = 150 mL of 1.50 M HCL