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4 votes
Write the equation of the line that
passes through (5,-7) and (0, -1)

User Adrianp
by
7.8k points

2 Answers

7 votes

4,3,2,1,0,-1, -2, -3, -4,

User Pseudosudo
by
8.3k points
0 votes

Equation of a line can be given by :

y = mx + b

Let's find the slope of the line (m) :


\mathcal{ \hookrightarrow \: (y_2 - y_1)/(x_2 - x_1) }


\mathcal{ \hookrightarrow \: ( - 1 - ( - 7))/(0 - 5) }


\hookrightarrow \: (6)/( - 5)


\hookrightarrow \: m = ( - 6)/(5)

now let's solve for b :


\hookrightarrow \: y = mx + b

Let's plug the values of x and y from the coordinates of a point .


\hookrightarrow \: - 7 = (( - 6)/(5) * 5) + b


\hookrightarrow \: - 7 = - 6 + b


\hookrightarrow \: b = - 1

now, let's put the value of m (slope) and b (y-intercept) in the equation.


\hookrightarrow \: y = mx + b


\boxed{ \boxed{\: y = ( - 6)/(5)x - 1 }}

That's All, I hope it helped ya

User Crazy Crab
by
8.1k points

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