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How many moles of ammonium nitrate are in 335 mL of 0.425 M NH4NO3?

User Yochi
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2 Answers

9 votes

Answer:

0.142

Step-by-step explanation:

User Eleddy
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5 votes

Answer:

0.142 moles.

You would have to convert the algorithm to a broken down version of the compound.

NH4NO3(aq] → NH+4(aq] + NO−3(aq]

The ammonium is removed for this case, concentration gets broken down to zero.

So here, if 1 liter is equal to 10 x 10 x 10 milliliters...

use the formula of n and c to help you figure out the moles.

C is equal to N divided by V, so in that case...

N equals C times V.

C times V is 0.425, or 17 over 40 in simplest form.

From there, multiply 17 over 40 by the current moles, cross out the liters, and multiply by 335, then, 10 to the power of -3. You have to flip it to negative, because it will cancel out either way. Change the equation by the liters, and you have 0.125

Hence, your correct answer is 0.125

User Jjack
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