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The reaction described by the equation X + Y Z shown to have the following rate law: R = K[X] [Y] What is the effect on the rate if the concentration of [X] is doubled and [Y] remains constant?
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The reaction described by the equation X + Y Z

shown to have the following rate law:
R = K[X] [Y]
What is the effect on the rate if the concentration
of [X] is doubled and [Y] remains constant?

User Sapna Bhayal
by
6.8k points

1 Answer

4 votes
rate is doubled because Rate is proportional to the concentration of X
User Shahnur
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7.5k points
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