HELP ASAP!!! The line (y-1)=(2/3)(x+1) contains point (a,-3). What is the value of a? Show your work.

asked Jan 13, 2022 96.5k views

1 vote

HELP ASAP!!!

The line (y-1)=(2/3)(x+1) contains point (a,-3).

What is the value of a? Show
your work.

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$\\ \sf\Rrightarrow y-1=(2)/(3)(x+1)$

$\\ \sf\Rrightarrow -3-1=(2)/(3)(a+1)$

$\\ \sf\Rrightarrow -4=(-2(a+1))/(3)$

$\\ \sf\Rrightarrow -2(a+1)=-4(3)$

$\\ \sf\Rrightarrow -2(a+1)=-12$

$\\ \sf\Rrightarrow a+1=(-12)/(-2)$

$\\ \sf\Rrightarrow a+1=6$

$\\ \sf\Rrightarrow a=6-1$

$\\ \sf\Rrightarrow a=5$

HowieH answered Jan 18, 2022

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