Question

4. Find the equation of the lines described.

A. Find the equation of the line parallel to y = 3x -5
and passing through
(-4, 7).

Answer 1

y = 3x + 19

Explanation:

Apply point-slope form. Our point (y1, y2) is (-4, 7) and our slope (m) is 3. The slope of y = 3x - 5 is 3 because it is "m" in y = mx + b. Parallel lines have the same slope.

y - y1 = m(x-x1)

y - 7 = 3(x-(-4))

y - 7 = 3(x+4)

y - 7 = 3x + 12

y = 3x + 19