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Find the zeros of f(x)=-x^2+6x+27
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4 votes
Find the zeros of f(x)=-x^2+6x+27

User Flordeliza
by
7.6k points

1 Answer

3 votes

Answer:

Zeroes of this function are -3 and 9.

Explanation:

Using quadratic formula we have:

(-6 +-
\sqrt{6^(2)-4(-1)(27) }) / 2(-1)

= -3, 9

User Kemal Tezer Dilsiz
by
6.8k points
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