Answer:
J' (-5, -6)
K' (-7, -7)
L' (-9, -6)
M' (-7, -3)
Explanation:
From inspection of the image:
J (6, 5)
K (7, 7)
L (6, 9)
M (3, 7)
y = -x ⇒ x = -y
So if we reflect the points over the line y = -x then
(x, y) → (-y, -x)
Therefore,
J (6, 5) → J' (-5, -6)
K (7, 7) → K' (-7, -7)
L (6, 9) → L' (-9, -6)
M (3, 7) → M' (-7, -3)