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Geometry > L.5 Reflections: graph the image SM9

Graph the image of kite JKLM after a reflection over the line y = -x.
1041
L
2
8
og
M
K
6
4
J
2
х
-10
-8
-6
-4
-2
2
4
6
8
10
-2
-4
-6
-8
-10
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Geometry > L.5 Reflections: graph the image SM9 Graph the image of kite JKLM after-example-1
User Cleverpaul
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2.9k points

2 Answers

25 votes
25 votes

The points are

  • J(6,5)
  • K(7,7)
  • L(6,9)
  • M(3,7)

The rule here is (x,y)=(-y,-x)

Now

new points

  • J'(-5,-6)
  • K'(-7,-7)
  • L'(-9,-6)
  • M'(-7,-3)
User Test Team
by
3.0k points
12 votes
12 votes

Answer:

J' (-5, -6)

K' (-7, -7)

L' (-9, -6)

M' (-7, -3)

Explanation:

From inspection of the image:

J (6, 5)

K (7, 7)

L (6, 9)

M (3, 7)

y = -x ⇒ x = -y

So if we reflect the points over the line y = -x then

(x, y) → (-y, -x)

Therefore,

J (6, 5) → J' (-5, -6)

K (7, 7) → K' (-7, -7)

L (6, 9) → L' (-9, -6)

M (3, 7) → M' (-7, -3)

Geometry > L.5 Reflections: graph the image SM9 Graph the image of kite JKLM after-example-1
User Xiaohu Wang
by
2.4k points