79.8k views
3 votes
Solve for x

R=x-b/n

Show work

User David Berg
by
7.8k points

1 Answer

3 votes

Explanation:

There are several methods to solve equations of the type AX = XB. These type of equations occur in domains like robotics, for which solutions have been proposed like the Tsai and Lenz method [IEEE 1987], for example. 1) I feel solving the equation XA = XB is not the same as solving the known form AX = XB. Am I right? 2) Neither can it be solved like the Sylvester equation, because even that requires AX+XB=CAX+XB=C form. What i have is XA=XBXA=XB, a redundant set of equations. That is,

A1.XA2.XAn.X=X.B1=X.B2⋮=X.BnA1.X=X.B1A2.X=X.B2⋮An.X=X.Bn

If i am correct, these could be rewritten into another form like AX=BXAX=BX. Should i rewrite the equation and try to solve this problem using any other existing methods?

User Kerrine
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.