Question

100 POINTS! PLEASE ANSWER ONLY IF YOU KNOW

Find the probability of “landing” in the shaded region of the figures below. Round your answer to the nearest hundredth.

Answer 1

4

We know that

Area of rectangle = lb

Area = 10(20)

Area = 200 m²

Shaded region = πr²

=> 2 × 22/7 × (10/2)²

=> 2 × 22/7 × 10/4

=> 157 m²

Probability = 157/200 = 78.5%

5.

Area of the biggest circle = πr²

= 22/7 × (20)²

= 1256.6

Area of shaded region

π(10² - 5²)

π(100 - 25)

3.14(75)

235.6

Probability = 235.6/1256.6 = 18.7%

Answer 2

#4

Area of rectangle:

• A = lw = 10*20 = 200 m²

Shaded area:

• A = 2πr² = 2π(10/2)² = 157.079 m²

Probability:

• P = 157.079/200 ≈ 0.785 or 78.5%

#5

Area of bigger circle:

• A = πr² = π(20)² = 1256.637 m²

Shaded area:

• A = π(10² - 5²) = 235.619 m²

Probability:

• P = 235.619/1256.637 ≈ 0.187 or 18.7%