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2. What is the midpoint of the line segment with endpoints (-7, 2) and (13,-6)?
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3 votes
2. What is the midpoint of the line segment with endpoints (-7, 2) and (13,-6)?

User Dayvid Oliveira
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1 Answer

3 votes

Answer:

The midpoint is (3, -2)

Explanation:


m = ((x1 + x2)/(2), (y1 + y2)/(2))\\m = ((-7 + 13)/(2), (2-6)/(2))\\m = ((6)/(2), (-4)/(2))\\m = (3, -2)

User OpenCage
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